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(i)The orange flavoured candy?

(ii) a lemon flavoured candy?

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Let the event of taking out a candy out of a bag be E. Then

(i) Since the bag contains orange flavoured candies only .Therefore the chances of the candy being taken out of an orange flavoured candy will be equal to the total number of candies. Now we know that, Probability=$\dfrac{{{\text{No}}{\text{. of favourable outcomes}}}}{{{\text{Total number of outcomes}}}} = \dfrac{{{\text{Number of orange candies being taken out}}}}{{{\text{Total number of candies}}}}$

Since, Number of candies taken out is equal to the total number of candies, then

$ \Rightarrow {\text{P}}\left( {\text{E}} \right) = \dfrac{{{\text{Total number of candies}}}}{{{\text{Total number of candies}}}} = 1$

Answer-Hence the Probability of Rahi taking out an orange flavoured candy is$1$.

(ii) Since there are no lemon flavoured candies in the bag. So the event of taking out a lemon flavoured candy is $ = 0$

So , Probability=$\dfrac{{{\text{No}}{\text{. of favourable outcomes}}}}{{{\text{Total number of outcomes}}}} = \dfrac{{{\text{Number of lemon candies being taken out}}}}{{{\text{Total number of candies}}}}$

Since the event is zero so the Probability will also be $0$ .

$ \Rightarrow {\text{P}}\left( {\text{E}} \right) = 0$